Preparation of 0.1 N H2SO4 (Sulfuric Acid) Solution

How to Prepare 1 N H2SO4 (Sulfuric Acid) Solution
Preparation of 0.1 N H2SO4 (Sulfuric Acid) Solution

Sulfuric acid is a well-known mineral acid that is also known as vitriol oil. It is largely made up of three elements: oxygen, hydrogen, and sulfur. Sulfuric acid, often known as H2SO4, is a colorless, odorless, and viscous chemical fluid.

Equivalent Weight of H2SO4

The concentration of acid or base in a solution is measured using normality (N). Normality and molarity are connected considering that molarity measures the concentration of ions and compounds in the solution, while normality reflects the molar concentration of an acid or basic component.

The amount of protons (H+) or hydroxides (OH) that react with each other determines the normality of an acid-base reaction. Consider a 1 M solution of sulfuric acid, H2SO4. The number of moles of protons in the solution is the normality. Because in H2SO4, each molecule contains two protons, the normality is 2 N.

To determine how many grams of sulfuric acid you will need, you will first need to calculate the equivalent weight of H2SO4. We can calculate the equivalent mass using the following equation:

Equivalent weight = (molecular weight)/(number of equivalent moles)

The molecular weight of H2SO4 is 98.07 g/mol.

The number of acid hydrogen in the compounds is 2.

or, Equivalent weight = 98.07g/mol/2 = 49.035

Therefore, the Equivalent weight is 49.035 g/mol.

Required Mass of H2SO4

Calculating the amount of sulfuric acid needed to make the appropriate volume of solution. We may use the following formula to determine the required mass of sulfuric acid:

Grams of compound needed = (N desired) x (equivalent mass) x (volume in liters)

Desired N is 0.1,

The equivalent mass is 49.035 g/mol

Grams of compound needed = (N desired) x (equivalent mass) x (volume in liters)

Grams of compound needed = 0.1N x 49 x 1 litre = 4.9 grams

Therefore, the grams of compound required is 4.9 grams.

Required Volume of the Concentrated H2SO4

A 0.1 N solution requires 4.9 g of pure sulfuric acid powder (if available) diluted to 1 L. However, the acid is a liquid, and it is not 100 percent pure active sulfuric acid. You must calculate the amount of concentrated acid that contains 4.9 grams of sulfuric acid.

Because acid is a liquid, we must use the following formula to compute the volume of concentrated acid required:

Volume of concentrated acid required = (grams of acid needed) / (percent concentration x specific gravity)

Here,

Concentration percent of sulfuric acid H2SO4 = 97%

The volume of concentrated acid required = 4.9 grams

Specific gravity = 1.84  g/cm3

The volume of concentrated acid required = (grams of acid needed) / (percent concentration x specific gravity)

Volume of concentrated acid required = 4.9 grams / (0.97 x 1.84) = 2.75 mL.

If you take 2.75 mL of concentrated sulfuric acid and dilute it to 1 L, you will get 0.1N H2SO4.

Preparation of 0.1 N H2SO4 Solution

Glassware and Apparatus Required

For the Preparation of 0.1 N H2SO4 (sulfuric acid) solution you need to following apparatus:

  • Beaker
  • Volumetric flask
  • Measuring cylinder
  • Pipette
  • Pipette bulb
  • Glass rod
  • Concentrated sulfuric acid (H2SO4)
  • Distilled water,

The procedure of Preparing 0.1 N Sulfuric Acid Solution

For the Preparation of 0.1 N H2SO4 (sulfuric acid) solution you need to follow the given steps:

  • Step 1: Take a volumetric flask of 1 L.
  • Step 2: Add 500 mL of distilled water to the flask
  • Step 3: Using a pipette take 2.75 mL of conc. H2SO4 and mix it with 500 mL of distilled water in the flask.
  • Step 4: Mix it properly.
  • Step 5: Allow it to cool at room temperature.
  • Step 6: Adjust the volume to 1 litre adding the distilled water to the solution.

Video on Preparation of 0.1 N H2SO4 (Sulfuric Acid) Solution

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Jyoti Bashyal

Jyoti Bashyal is a Ph.D. student in the Department of Chemistry and Chemical Biology at the University of New Mexico, USA. Her research focuses on understanding the structure-function relationships in glucose transporters (GLUTs) and their implications for diseases such as cancer, diabetes, and metabolic syndromes. By investigating how these proteins work at the molecular level, Jyoti aims to contribute to drug discovery efforts targeting these critical transporters. She is particularly interested in exploring how high-throughput protein expression and crystallization techniques can be applied to better understand carbohydrate-related proteins and their therapeutic potential. Blending her expertise in chemistry, biology, and computational tools, Jyoti is driven by a passion for solving complex scientific challenges. Outside the lab, she is a dedicated science communicator who loves making complex concepts approachable and engaging. Through writing and sharing her knowledge, she hopes to inspire curiosity and excitement about science. Jyoti’s goal is to connect groundbreaking discoveries with real-world impact, encouraging others to see the power and beauty of science in action.

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